Perhaps a bit feebly, you decide not to double (do you agree?) but partner is there. The play goes:
♥3 2 J Q
♣4 7 8 K
♥6 8 9 A
♦4 K 5 9
♣5 6 Q 8
♥K 5 ♦3 ♥7
Partner's ♣5 and ♦3 are present count.
Things seem to have gone OK so far. Now what?
Posted 2010-December-29, 17:48
Posted 2010-December-29, 17:58
gnasher, on 2010-December-29, 17:48, said:
Posted 2010-December-29, 18:08
Posted 2010-December-29, 18:08
BunnyGo, on 2010-December-29, 17:58, said:
Posted 2010-December-29, 18:12
Posted 2010-December-29, 18:21
JLOGIC, on 2010-December-29, 18:08, said:
Posted 2010-December-29, 18:33
JLOGIC, on 2010-December-29, 18:12, said:
Posted 2010-December-29, 19:01
Posted 2010-December-30, 15:55
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